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For a two step reaction,
$A ⇌ R + B$ $R + C \overset{k_{2}}{\to} P$
(Where, R is a reactive intermediate whose concentration is maintained at some low steady state throughout the reaction). If the concentration of C is very high then the order of reaction for formation of "P" is :

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$\frac{1}{2}$

answer is C.

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Detailed Solution

$\frac{d P}{d t} = k_{2} [C] [R]$ Using S.S.A. on R

We get, $k_{2} [C] [R] + k_{2}^{'} [B] [R] = k_{1}^{'} [A]$

$\Rightarrow [R] = \frac{k_{1}^{'} [A]}{k_{2} [C] + k_{2}^{'} [B]} = \frac{k_{1}^{'} [A]}{k_{2} [C]}$

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