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Q.

For a weak monobasic acid, if pKa = 4, then at a concentration of 0.01 M of the acid solution, the van’t Hoff factor is

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a

1.02

b

1.10

c

1.01

d

1.20

answer is C.

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Detailed Solution

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                      HA     H++ A- At equili,  C(1-α)            

 Given, pka=4  ka=10-4  ;  C=0.01M ka=2α=kaC=10-410-2=10-1=0.1 van't hoff factor, i=1+α1=1+0.1=1.1

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