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For a zero order reaction : $A ⟶ 2 B$ initial rate of a reaction is $10^{- 1} M \min^{- 1}$ If concentration of 'A' is 0.1 after 120 sec then what would be concentration of B after 60 sec.

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0.15 M

0.05 M

0.2 M

0.1 M

answer is A.

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Detailed Solution

In the reaction we have,

$\begin{aligned} 0.1 = a - 0.1 \times 2 \\ \underset{0.3 - x}{A} \to \underset{2 x}{2 B} \end{aligned}$

$\begin{array}{l} 2 x = 2 k t = 2 \times 0.1 \times 1 \\ [B]_{t} = 0.2 M \end{array}$

So concentration of B after 60 sec is 0.2 M.

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