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For a zero order reaction, initial concentration of the reactant is 2 M and after 60 minutes the concentration left is 0.5 M. Rate constant of the reaction is

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$0.05 M^{- 1} . \min^{- 1}$

$0.033 M^{- 1} . \min^{- 1}$

$0.025 M . \min^{- 1}$

$0.05 M . \min^{- 1}$

answer is C.

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Detailed Solution

$Given, a = 2 M; (a - x) = 0.5 M Thus x = 1.5 M x = Kt . . . . . . for zero order K = \frac{1.5 M}{60 minutes} = 0.025 M . \min^{- 1}$

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