For an airplane to take – off from rest the acceleration (m/s2 ) v/s time(s) graph is as shown. The distance travelled by the airplane in 6 s is

a=56t⇒V=∫56tdt=512t2⇒∫ds=∫512t2dt⇒s=30m

For an airplane to take – off from rest the acceleration (m/s2 ) v/s time(s) graph is as shown. The distance travelled by the airplane in 6 s is

a=56t⇒V=∫56tdt=512t2⇒∫ds=∫512t2dt⇒s=30m

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For an airplane to take – off from rest the acceleration (m/s² ) v/s time(s) graph is as shown. The distance travelled by the airplane in 6 s is

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20 m

30 m

40 m

50 m

answer is B.

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$\begin{array}{l} a = (\frac{5}{6}) t \Rightarrow V = \int (\frac{5}{6} t) dt = (\frac{5}{12}) t^{2} \\ \Rightarrow \int ds = \int \frac{5}{12} t^{2} dt \Rightarrow s = 30 m \end{array}$

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For an airplane to take – off from rest the acceleration (m/s2 ) v/s time(s) graph is as shown. The distance travelled by the airplane in 6 s is

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For an airplane to take – off from rest the acceleration (m/s² ) v/s time(s) graph is as shown. The distance travelled by the airplane in 6 s is