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For an aqueous solution of $0.1 M Ma NO 3 2$ osmotic pressure at $300 K$ is found to be 6.576atm. Percentage dissociation of $Ba NO 3 2$ in solution is nearly?

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91.3%

100%

74%

84%

answer is B.

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Detailed Solution

$\begin{matrix} π = i \cdot CST \\ 6.576 = (1 + 2 α) 0.1 \times 0.0821 \times 300 \\ α = \frac{1.67}{2} = 84 % \end{matrix}$

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