For an electron to have the same de Broglie wave length as that of a Deuteron, its velocity should be--- times that of Deuteron

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1/1836

1/3672

1836

3672

answer is C.

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Detailed Solution

$λ = \frac{h}{m v} \frac{h}{m_{e} v_{e}} = \frac{h}{m_{D} v_{D}} \frac{V_{e}}{V_{D}} = \frac{m_{D}}{m_{e}} \frac{3.343 \times 10^{- 27}}{9.1 \times 10^{- 31}} V_{e} = 3674 \times V_{D}$

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