For an elementary chemical reaction, A2⇌k1k-12 A, the expression for d[A]dt is

Rate =-d[A]dt=12d[A]dtdt d[A]dt=2k1A2-2K-1A212d[A]dt=k1A2-k-1[A]2Hence the correct answer is (D) 2k1 A2-k-1[ A]2

For an elementary chemical reaction, A2⇌k1k-12 A, the expression for d[A]dt is

Rate =-d[A]dt=12d[A]dtdt d[A]dt=2k1A2-2K-1A212d[A]dt=k1A2-k-1[A]2Hence the correct answer is (D) 2k1 A2-k-1[ A]2

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For an elementary chemical reaction, $A_{2} \underset{k_{- 1}}{\overset{k_{1}}{⇌}} 2 A$ , the expression for $\frac{d [A]}{dt}$ is

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$k_{1} [A_{2}] - k_{- 1} [A]^{2}$

$2 k_{1} [A_{2}] - k_{- 1} [A]^{2}$

$k_{1} [A_{2}] + k_{- 1} [A]^{2}$

$2 k_{1} [A_{2}] - k_{- 1} [A]^{2}$

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Rate $= - \frac{d [A]}{d t} = \frac{\frac{1}{2} \frac{d [A]}{d t}}{d t} \frac{d [A]}{d t} = 2 k_{1} [A_{2}] - 2 K_{- 1} {[A]}^{2}$

$\frac{1}{2} \frac{d [A]}{d t} = k_{1} [A_{2}] - k_{- 1} [A]^{2}$

Hence the correct answer is (D) $2 k_{1} [A_{2}] - k_{- 1} [A]^{2}$

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For an elementary chemical reaction, A2⇌k1k-12 A, the expression for d[A]dt is

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For an elementary chemical reaction, $A_{2} \underset{k_{- 1}}{\overset{k_{1}}{⇌}} 2 A$ , the expression for $\frac{d [A]}{dt}$ is