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For an elementary chemical reaction $A 2 ⇌ k 1 k − 1 2 A$ ,
The expression for $d [A] d t$ is

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2 k 1 A 2 − 2 k − 1 [A] 2

k 1 A 2 + k − 1 [A] 2

2 k 1 A 2 − k − 1 [A] 2

k 1 A 2 − k − 1 [A] 2

answer is D.

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Detailed Solution

$A_{2} \frac{k_{1}}{k_{- 1}} 2 A - \frac{1}{2} \frac{d [A]}{d t} = k_{- 1} [A_{2}] \Rightarrow \frac{d [A]}{d t} = 2 k_{1} [A_{2}] - 2 k_{- 1} {[A]}^{2}$

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