For an elementary reaction the variation of rate constant (k) with temperature is given by the following equation.

${\log }_{10}k=5.4-\frac{100}{\mathrm{T}}$ where 'T' is temperature on Kelvin scale and k is in terms of ${\sec }^{-1}$. Identify the incorrect option.

There is no finite temperature at which rate constant can be $4\times {10}^6{\sec }^{-1}$

Fraction of activated molecules will be $e^{-100/T}$at any temperature.

Activation energy for the reaction will be approx. 460.6 $\mathrm{cal}$

Rate of reaction will vary linearly with concentration of reactant.