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For an ideal gas V-T curves as constant pressures P1 & P2 are shown in figure - from the figure

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$P_{1} > P_{2}$

$P_{1} \geq P_{2}$

$P_{1} < P_{2}$

$P_{1} = P_{2}$

answer is B.

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Detailed Solution

$\frac{PV}{T} = constant$

$P (slope) = constant$

$P (\tan θ) = constant$

$p α \frac{1}{\tan θ} here θ_{1} > θ_{2}$

$P_{1} < P_{2} \Rightarrow P_{2} > P_{1}$

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