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For an object moving with uniform acceleration travelling 50m in 5^th sec, 70m in 7^th second

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Its travel 100m in 9^th second

Its average velocity during 9^th second is 90 m/s

Its initial velocity is 5 m/s

Its acceleration is $20 m / s^{2}$

answer is A, D.

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Detailed Solution

$s_{n} = u + a (n - \frac{1}{2})$

$50 = u + a (5 - \frac{1}{2})$

$70 = u + a (7 - \frac{1}{2})$

After subtraction

$20 = a (\frac{13 - 9}{2})$

$a = 10 m / s^{2}$

$50 = u + 10 \times \frac{9}{20} \Rightarrow u = 5 m / s^{2}$

$s_{9} = 5 + 10 (9 - \frac{1}{2}) = 5 + \frac{10 \times 17}{2} = 90 m$

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