For any non-zero real value of m, the equation of the parabola to which the line $\mathrm{mx}-\mathrm{y}+10+{\mathrm{m}}^2=0$ is a tangent, is

$$\begin{gathered} \mathrm{mx}-\mathrm{y}+10+{\mathrm{m}}^2=0 \\ \mathrm{y}=\mathrm{mx}+10+{\mathrm{m}}^2 \end{gathered}$$

By verification ,for option (3)

$$\begin{gathered} {\mathrm{x}}^2=-4(\mathrm{y}-10) \\ \tan gent in slope form is \\ \mathrm{y}-10=m\mathrm{x}-{\mathrm{am}}^2 \\ \mathrm{y}=\mathrm{mx}+10+{\mathrm{m}}^2 \end{gathered}$$