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Q.

For any real number x, let [x] denote the largest integer less than equal to x. Let f be a real valued function defined on the interval [–10,10] by f(x)=x[x], if (x) is odd 1+[x]x if (x) is even 

Then the value of π2101010f(x)cosπxdx is:

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a

4

b

2

c

1

d

0

answer is A.

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Detailed Solution

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f(x) is periodic function whose period is 2

π2101010f(x)cosπxdx=π210×1002f(x)cosπxdx=π201(1x)cosπxdx+12(x1)cosπxdx

Using by parts =π2×4π2=4

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