For any two rational numbers a and b, a5×b5 is equal to

(a)5×(b)5=(a×b)5 (∵am×bm=(a×b)m)

For any two rational numbers a and b, a5×b5 is equal to

(a)5×(b)5=(a×b)5 (∵am×bm=(a×b)m)

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For any two rational numbers a and b, $a^{5} \times b^{5}$ is equal to

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{(a \times b)}^{0}

{(a \times b)}^{10}

{(a \times b)}^{5}

{(a \times b)}^{25}

answer is C.

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{(a)}^{5} \times {(b)}^{5} = {(a \times b)}^{5}

(∵ a^{m} \times b^{m} = {(a \times b)}^{m})

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For any two rational numbers a and b, $a^{5} \times b^{5}$ is equal to