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For decolorization of 1 mol of KMnO₄, the mol of H₂O₂ required is

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3/2

5/2

7/2

1/2

answer is B.

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Detailed Solution

$2 {KMnO}_{4} + 3 H_{2} {SO}_{4} ⟶$ $K_{2} {SO}_{4} + 2 {MnSO}_{4} + 3 H_{2} O +$ 5O

$5 H_{2} O_{2} + 5 O ⟶ 5 H_{2} O + 5 O_{2}$

$2 {KMnO}_{4} + 3 H_{2} {SO}_{4} + 5 H_{2} O_{2} ⟶$ $K_{2} {SO}_{4} + 2 {MnSO}_{4} + 8 H_{2} O + 5 O_{2}$

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