For different functions given under the List I match the corresponding number of points of non-differentiability given under the list II

	List I		List II
1)	$f\left(x\right)=|x^2-1|{\cos }^{-1}\left(\frac{1-x^2}{1+x^2}\right)$	(i)	0
2)	$f\left(x\right)=\left(\cos x\right).{\sin }^{-1}\left(\sin x\right)$	(ii)	1
3)	$f\left(x\right)=|2x^2-x-3|\left(\sin \pi x\right)$	(iii)	2
4)	$f\left(x\right)=x^{2/3}{(x-1)}^{4/7}$	(iv)	3

$f\left(x\right)=|x^2-1|{\cos }^{-1}\left(\frac{1-x^2}{1+x^2}\right)$
$|x^2-1|$  is non-differentiable at  $x=\pm 1$, where ${\cos }^{-1}\left(\frac{1-x^2}{1+x^2}\right)$ doe not vanish and   ${\cos }^{-1}\left(\frac{1-x^2}{1+x^2}\right)$  is non-differentiable at x = 0, where $|x^2-1|$ does not vanish
So, there are three points of non-differentiability
B)  $f\left(x\right)=\left(\cos x\right).{\sin }^{-1}\left(\sin x\right)$ is differentiable everywhere ,${\sin }^{-1}\left(\sin x\right)$ is non – differentiable at  $x=(2n+1)\frac{\pi }{2},n\in Z$, where cos x vanishes.
So,  $f\left(x\right)$ is differentiable everywhere.
C)   $f\left(x\right)=|2x^2-x-3|\left(\sin \pi x\right)=|2x-3||x+1|\left(\sin \pi x\right)$
$\left(\sin \pi x\right)$ is differentiable everywhere $|2x^2-x-3|$  is non-differentiable at  $x=-1,3/2$,  and  at x=-1  $\sin \left(\pi x\right)$ vanishes
So, there is only one point of non-differentiability, i.e.,  $x=3/2$.
D)  $f\left(x\right)=x^{2/3}{(x-1)}^{4/7}$
$x^{2/3}$  is non-differentiable at x = 0, where  ${(x-1)}^{4/7}$ does not vanish ${(x-1)}^{4/7}$  is non-differentiable at x = 1, where  $x^{2/3}$  does not vanish
So, there are two points of non-differentiability, x = 0, 1.