Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

For dissociation of NH3 giving N2 and H2 gases, the partial pressures at equilibrium are 100, 80, 80 torr respectively. If some N2 gas is removed and at new equilibrium partial pressure of H2 becomes 128 torr then the partial pressure of N2 remaining will be approx:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

71 torr

b

72 torr

c

8 torr

d

9 torr

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The reaction takes place as;

2NH3N2+3H2 KP=80×8031002

1008080100P?80+3P2=128=68P=32 

80×8031002=PN2×(128)s682 PN2=9atm

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon