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Q.

For each xR  let [x] denotes greatest integer  less than or equal to x then limx0-x([x]+|x|)sin[2]|x|  

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a

-sin 1

b

0

c

1

d

sin 1

answer is A.

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Detailed Solution

limx0-x([x]+|x|)sin[x]|x|=limx0x(1x)sin(1)x

                                     =limx0(1+x)sin1=-sin1

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