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For electron moving in n^th orbit of H-atom the angular velocity is proportional to

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a

n

b

n³

c

1/n

d

1/n³

answer is D.

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Detailed Solution

$\frac{m v^{2}}{r} = \frac{Z e^{2}}{4 π ε_{0} r^{2}} a n d m v r = \frac{n h}{2 π}$

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