For emission line of H-atom from n₁ = 8 to n_f = n, the plot of wave no. against $[\frac{1}{n^{2}}]$ will be : (R_H is Rydberg constant in the wave no. unit)

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linear with intercept - R_H

non-linear

linear with slope R_H

linear with slope - R_H

answer is D.

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Detailed Solution

$\begin{array}{l} \bar{v} = \frac{1}{λ} = R_{H} [\frac{1}{8^{2}} - \frac{1}{n^{2}}] = \frac{R_{H}}{64} - \frac{R_{H}}{n^{2}} \\ = C + mX \end{array}$
$Thus, \bar{ν} vs \frac{1}{n^{2}}$ plots are linear with slope - R_H

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