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For full wave rectifier 100W ac input power is applied. DC output power obtained is 85W . then efficiency of rectifier is

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85%

100%

42.5%

90%

answer is A.

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Detailed Solution

$η = \frac{P_{d c}}{P_{a c}} \times 100 = \frac{85}{100} \times 100 = 85 %$

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