For ground to ground projection range of a projectile is 240 m and its angle of projection is 450. Then equation of its trajectory is

 $20 y =60 x - \frac{x^2}{240}$ 

$y = x -\frac{x^2}{240}$  $y=sqrt\{3\}x-frac\{\{\{x\}^\{2\}\}\}\{120\}$

  30 y =$y=frac\{x\}\{sqrt\{3\}\}-frac\{\{\{x\}^\{2\}\}\}\{480\}$x - $\frac{x^2}{80}$

  y = 30 x - $\frac{x^2}{80}$$vec\{u\},,=,,left(\; 20hat\{i\}+20sqrt\{3\}hat\{j\}\; right)$