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For Half Wave rectifier 200W a c input power applied. DC output power obtained is 85W then the efficiency of the rectifier is

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100%

85%

42.5%

200%

answer is C.

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Detailed Solution

$η = \frac{P_{d c}}{P_{a c}} \times 100 = \frac{85}{200} \times 100 = 42.5 %$

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