Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

For hyperbola  x2a2y2b2=1, let n be the number of points on the plane through which perpendicular tangents are drawn.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

none of these

b

If  n > 1, then  1<e<2

c

If  n = 0, then  e>2

d

If n = 1, then  e=2

answer is A, B, C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

(a, b, c) Locus of point of intersection of perpendicular tangent is the director circle, x2 + y2 = a2  b2 
e2=1+b2a2, If  a2 > b2, then there are infinite points (or more than 1) points on the circle  e2<2e<2
If  a2 < b2, there doesn’t exist any point on the plane  e2>2e>2
If   a2 = b2, there is exactly one point
(centre  of the hyperbola)  e=2

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring