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For I₂+2e→2I^–, standard reduction potential = +0.54 volt. For 2Br^-–→Br₂+2e^–, standard oxidation potential = –1.09 volt. For Fe →Fe²⁺ + 2e–, standard oxidation potential = +0.44 volt. Which of the following reactions is non-spontaneous?

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${Br}_{2} + 2 I^{-} \to 2 {Br}^{-} + I_{2}$

$Fe + {Br}_{2} \to {Fe}^{2 +} + 2 {Br}^{-}$

$Fe + I_{2} \to {Fe}^{2 +} + 2 I^{-}$

$I_{2} + 2 {Br}^{-} \to 2 I^{-} + {Br}_{2}$

answer is D.

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Detailed Solution

$I_{2} + 2 {Br}^{-} \to {Br}_{2} + 2 I^{-}$

electrode with higher SRP acts as cathode and electrode with lower SRP acts as anode, EMF of cell is positive and spontaneous reaction

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