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Q.

For intensity I of a light of wavelength 5000 A the photoelectron saturation current is 0.40 µA and stopping potential is 1.36 V, the work function of metal is

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a

2.47 eV

b

0.43 eV

c

1.10 eV

d

1.36 eV

answer is C.

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Detailed Solution

By  using  E=Wo+Kmax⇒E=123755000=2.475eV  and  Kmax=eVo=1.36eVSo  2.475=Wo+1.36⇒Wo=1.1eV

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For intensity I of a light of wavelength 5000 A the photoelectron saturation current is 0.40 µA and stopping potential is 1.36 V, the work function of metal is