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Q.

For ionization of sodium atoms the difference between ionization enthalpy and ionization energy is equal to

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a

$\frac{5 RT}{2}$

b

$- \frac{5 RT}{2}$

c

$- \frac{5 T}{2 R}$

d

$\frac{2 RT}{5}$

answer is A.

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Detailed Solution

Ionization enthalpy = ionization energy + $\frac{5 RT}{2}$

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