For loop OABCDEO carrying current I, the magnetic field at point P(a, 0, 0) will be

see full answer

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

\frac{μ_{0} I \sqrt{2}}{π a} [- \hat{k} - \hat{j}]

\frac{μ_{0} I}{\sqrt{2} π a} [- \hat{k} - \hat{j}]

\frac{μ_{0} I}{2 π a} [- \hat{k} - \hat{j}]

\frac{μ_{0} I}{π a} [- \hat{k} - \hat{j}]

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Field due to AB at P is

$B = \frac{μ_{0} i}{4 π a} 2 (\frac{1}{\sqrt{2}}) (- \hat{k})$

Field due to DE at P is

$B = \frac{μ_{0} i}{4 π a} 2 (\frac{1}{\sqrt{2}}) (- \hat{j})$

Field due to EO at P is

$B = \frac{μ_{0} i}{4 π a} (\frac{1}{\sqrt{2}}) (- \hat{j})$

Field due to CD at P is

$B = \frac{μ_{0} i}{4 π a} (\frac{1}{\sqrt{2}}) (- \hat{j})$

Field due to OA at P is

$B = \frac{μ_{0} i}{4 π a} (\frac{1}{\sqrt{2}}) (- \hat{k})$

Field due to BC at P is

$B = \frac{μ_{0} i}{4 π a} (\frac{1}{\sqrt{2}}) (- \hat{k})$

${\vec{B}}_{P} = \frac{μ_{0} i}{\sqrt{2} π a} (- \hat{k} - \hat{j})$

Watch 3-min video & get full concept clarity