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For N₂O_4(g) $⇌$ 2NO_2(g) at 12.18K, correct relation between K_p and K_c is

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K_p - K_c = 1

K_p - K_c = 0

K_p + K_c = 0

K_p + K_c = 1

answer is A.

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Detailed Solution

$∆ n_{g} = 1$

K_p=K_c(RT)¹

$\frac{1}{R} = \frac{1}{0.0821} =$ 12.18 = T

K_p= K_c(R $\times$ $\frac{1}{R}$ )

K_p = K_c

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