For nitrogen atom, if $5^{\mathrm{th}}$ electron has quantum numbers $\mathrm{n}=2,\mathrm{l}=1,\mathrm{m}=-1,\mathrm{s}=+\frac{1}{2}$ then, what will 2 be the correct option for $6^{\mathrm{th}}$ electron's quantum numbers?

For nitrogen atom, if $5^{\mathrm{th}}$ electron has quantum numbers $\mathrm{n}=2,\mathrm{l}=1,\mathrm{m}=-1,\mathrm{s}=+\frac{1}{2}$ then, the correct option for $6^{\mathrm{th}}$ electron's quantum numbers $\begin{array}{r}n=2,l=1,m=0,s=+\frac{1}{2}\end{array}$

Since $2{\mathrm{p}}_{\mathrm{x}}$ has a fifth electron, its n, l, m, and s values are $2,-1,1,+\frac{1}{2}$, respectively.

Since $2{\mathrm{p}}_y$ has a 6th electron, its n, l, m, and s values are $2,1,1,+\frac{1}{2}$respectively.