For n∈z;cos(2θ)=5+14 implies θ=

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For $n \in z; \cos (2 θ) = \frac{\sqrt{5} + 1}{4}$ implies $θ =$

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2 n π \pm \frac{π}{5}, n \in z

\frac{n π}{5} + {(- 1)}^{n} . \frac{π}{10}, n \in z

n π \pm \frac{π}{10}, n \in z

n π \pm \frac{π}{5}, n \in z

answer is D.

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\cos (2 θ) = \cos (\frac{\sqrt{5} + 1}{4}) = \cos \frac{π}{5}

$2 θ = 2 n π \pm \frac{π}{5}$

$θ = n π \pm \frac{π}{10}$

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