For one mole of an ideal gas, increasing the temperature from 10° C to 20° C

lnitial temperature = 283K

 Final temperature = 293K

$$\begin{gathered} K{E}_1=\frac{3R{T}_1}{2},K{E}_2=\frac{3R{T}_2}{2} \\ \frac{K{E}_1}{K{E}_2}=\frac{T_1}{T_2}=\frac{283}{293}=0.96 \\ \begin{array}{l}K{E}_2=1.04K{E}_1\\ v_{-ms}=\sqrt{\frac{3RT}{M}}\Rightarrow \frac{v_1}{v_2}=\sqrt{\frac{T_1}{T_2}}\Rightarrow \sqrt{\frac{283}{293}}\end{array} \\ {v}_2=v_1\sqrt{\frac{293}{283}}=1.02v_1 \end{gathered}$$

Both average K. E. and$\mathrm{rms}$ velocity increase but not significantly