For one mole of ideal gas if p=P01+V2V0 where P0 and V0 are constant, then temperature of gas when V=V0 is:

Step 1,The ideal gas equation is rearranged as,P=P02Step 2,T=PVnR=P02×V01×R=P0V02R

For one mole of ideal gas if p=P01+V2V0 where P0 and V0 are constant, then temperature of gas when V=V0 is:

Step 1,The ideal gas equation is rearranged as,P=P02Step 2,T=PVnR=P02×V01×R=P0V02R

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For one mole of ideal gas if $p = \frac{P_{0}}{1 + (\frac{V^{2}}{V_{0}})}$ where $P_{0}$ and $V_{0}$ are constant, then temperature of gas when $V = V_{0}$ is:

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$\frac{P_{0} V_{0}}{R}$

$\frac{P_{0} V_{0}}{4 R}$

$\frac{P_{0} V_{0}}{2 R}$

$\frac{P_{0} V_{0}}{3 R}$

answer is C.

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Detailed Solution

Step 1,

The ideal gas equation is rearranged as,

$P = \frac{P_{0}}{2}$
Step 2,

$T = \frac{P V}{n R} = \frac{\frac{P_{0}}{2} \times V_{0}}{1 \times R}$

$= \frac{P_{0} V_{0}}{2 R}$

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For one mole of ideal gas if p=P01+V2V0 where P0 and V0 are constant, then temperature of gas when V=V0 is:

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For one mole of ideal gas if $p = \frac{P_{0}}{1 + (\frac{V^{2}}{V_{0}})}$ where $P_{0}$ and $V_{0}$ are constant, then temperature of gas when $V = V_{0}$ is: