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For one of the element various successive ionization enthalpies (in kJ mol^–1) are given below
The element is

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answer is D.

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Detailed Solution

As we can see that 4th ionization energy is exceptionally high, that means it should have a noble gas configuration.

It is very difficult to remove an electron from a fully filled valence orbital.

It means the element belongs to 3rd group.

And, among following options Al belong to third group.

Hence, option(D) is the answer.

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