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Q.

For particle P revolving round the centre O with radius of circular path r and angular velocity ω, as shown in below figure, the projection of OP on the x-axis at time t is

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a

x(t)=rcos⁡(ωt)

b

x(t)=rcos⁡ωt−π6ω

c

x(t)=rcos⁡ωt+π6

d

x(t)=rsin⁡ωt+π6

answer is C.

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Detailed Solution

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By using concept of phasor diagram. Particle starts from π/6.

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x=Acos⁡(ωt+ϕ)
x=r cos⁡(ωt+π/6)

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