For PbCl2, the expression for solubility product [ksp] is

PbCl2⇌Pb+2+2Cl¯ s 2s ∴ksp=s⋅(2s)2=4s3

PbCl2⇌Pb+2+2Cl¯ s 2s ∴ksp=s⋅(2s)2=4s3

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For PbCl₂, the expression for solubility product [k_sp] is

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4s³

27s⁴

s²

s³

answer is C.

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${PbCl}_{2} ⇌ {Pb}^{+ 2} + 2 \bar{Cl} s 2 s \begin{array}{l} ∴ k_{sp} = s \cdot (2 s)^{2} \\ = 4 s^{3} \end{array}$

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