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Q.

For positive integer n, let f(n)=sinnθ+cosnθ . Then f(3)f(5)f(5)f(7)=

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a

f(3)f(1)

b

f(2)

c

f(2)f(3)

d

f(1)f(3)

answer is A.

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Detailed Solution

f(3)f(5)f(5)f(7)=sin3θ+cos3θsin5θcos5θsin5θ+cos5θsin7θcos7θ

=sin3θ(1sin2θ)+cos3θ(1cos2θ)sin5θ(1sin2θ)+cos5θ(1cos2θ)

=sin3θcos2θ+cos3θsin2θsin5θcos2θ+cos5θ.sin2θ

=sin2θcos2θ(sinθ+cosθ)sin2θcos2θ(sin3θ+cos3θ)

=sinθ+cosθsin3θ+cos3θ=f(1)f(3)

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