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Q.

For reaction 2Fe3+(aq)+2I(aq)2Fe2+(aq)+I2(s)  the magnitude of the standard molar free energy change is ________ kJ 
(Round off to the Nearest Integer)
EFe2+Fe(s)0= 0.44V;   EFe3+Fe(s)0= 0.036V;  EI22I0= 0.54V;F=96500C  )

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answer is 45.

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Detailed Solution

Ecell0= EFe3+Fe2+0 EI22I0 = 0.772 V – 0.54 V = 0.232V
ΔG0= nFEcell0= 2 ×96500 ×0.232 ×103 kJ= 44.776 kJ  45 
 

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For reaction 2Fe3+(aq)+2I−(aq)→2Fe2+(aq)+I2(s)  the magnitude of the standard molar free energy change is ________ kJ (Round off to the Nearest Integer)EFe2+Fe(s)0= −0.44V;   EFe3+Fe(s)0= −0.036V;  EI22I−0= 0.54V;F=96500C  )