For reaction : NH3 (liq) +Na⟶ Warm P+Q↑Incorrect statement is :

Na+NH3(liq)⟶WarmNaNH2P+12H2(g)Q (a) NaNH2+H2O⟶NaOH+NH3 (Hydrolysis of NaNH2 ) (b) Alkali metal +H2⟶Δ Metal hydride (c) NH2−is stronger base than NH3 (d) Li+NH3⟶Li2NH+H2(g)

For reaction : NH3 (liq) +Na⟶ Warm P+Q↑Incorrect statement is :

Na+NH3(liq)⟶WarmNaNH2P+12H2(g)Q (a) NaNH2+H2O⟶NaOH+NH3 (Hydrolysis of NaNH2 ) (b) Alkali metal +H2⟶Δ Metal hydride (c) NH2−is stronger base than NH3 (d) Li+NH3⟶Li2NH+H2(g)

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For reaction : ${NH}_{3} (liq) + Na \overset{Warm}{⟶} P + Q ↑$
Incorrect statement is :

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Gas 'Q' reacts with heated alkali metals.

Anionic part of 'P' is weaker base than NH₃.

Gas Q is also produced, when Li metal is heated with NH₃ gas.

Hydrolysis of 'P' produces NH₃ gas.

answer is C.

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Detailed Solution

$Na + {NH}_{3} (liq) \overset{Warm}{⟶} \underset{P}{{NaNH}_{2}} + \underset{Q}{\frac{1}{2} H_{2} (g)}$
$(a) {NaNH}_{2} + H_{2} O ⟶ NaOH + {NH}_{3} (Hydrolysis of {NaNH}_{2})$
$(b) Alkali metal + H_{2} \overset{Δ}{⟶} Metal hydride$
$(c) {NH}_{2}^{-} is stronger base than {NH}_{3}$
$(d) Li + {NH}_{3} ⟶ {Li}_{2} NH + H_{2} (g)$