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For reaction $2 A (g) + 3 B (g) ⟶ 4 C (g) + D (s)$ Calculate work involved during reaction if reaction occurs at constant pressure and 300 K

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1200 cal

600 cal

150 cal

300 cal

answer is A.

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Detailed Solution

$w = - Δ n_{g} R T = + 1 \times 2 \times 300 = 600 cal$

Constant

$Work = - \int P d v \Rightarrow - P \int d v$

$Δ n g = 4 - (2 + 3) = - 1$

$\begin{array}{l} \Rightarrow - ∆ n gRT \\ \Rightarrow - 1 (- 1) \times 2 \times 300 \end{array}$

600 cal

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