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For reaction, ${PCl}_{3} (g) + {Cl}_{2} (g) ⇌ {PCl}_{5} (g)$ , the value of K_c at 250°C is 26.The"value of K_p at this temperature will be:

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0.605

0.57

0.83

0.46

answer is A.

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Detailed Solution

$\begin{array}{l} K_{p} = K_{c} (RT)^{Δn} \\ ∴ K_{p} = 26 \times (0 .0821 \times 523)^{- 1} = 0 .605 \end{array}$

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