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Q.

For SO₂Cl₂(g)→ SO₂(g) + Cl₂(g), Pressure of SO₂Cl₂ changed from 5 atm to 4 atm in 10 min. Then, pressure of SO₂Cl₂ at the end of 30 minutes will be (in atm)

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a

5.56

b

2.56

c

3.56

d

4.56

answer is A.

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Detailed Solution

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$At t = 10 \min, [A_{o}] = 5 atm, = 4 atm k = \frac{2.303}{t} \log \frac{[A_{o}]}{[A]} = \frac{2.303}{10} \log \frac{5}{4} = 0.0223 At t = 30 \min, 0.0223 = \frac{2.303}{30} \log \frac{5}{[A]} \log \frac{5}{A} = \frac{0.0223 \times 30}{2.303} ∴ [A] = 2.56 atm .$

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