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For the 1^storder reaction c is the concentration of the reactant at time ‘t’ and C_o is the initial concentration then ( C_o – C ) =

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$C o (1 - e^{- k t})$

$C o e^{- k t}$

$C o (1 + e^{k t})$

$C o e^{k t}$

answer is A.

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Detailed Solution

$k = \frac{1}{t} \log e (\frac{C o}{C})$
$K t = \log e (\frac{C o}{C})$
$- K t = \log e (\frac{C}{C o})$
$\frac{C}{C o} = e^{- k t}$
$1 - \frac{C}{C o} = 1 - e^{- k t}$
$\frac{C o - C}{C o} = 1 - e^{- k t}$
$(C o - C) = C o (1 - e^{- k t})$

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