For the AC circuit shown, the reading of ammeter and voltmeter are 5A and volts  $50\sqrt{5}$ volts respectively, then
 
 

 $i_{rms}=5A$
Reading of voltmeter  $=i_{rms}\sqrt{R^2+X_c^2}$
From this  $X_c=20\Omega \Rightarrow w={10}^{3}rad/s\Rightarrow$
$f=\frac{1000}{2\pi }\therefore X_L=\omega L=20\Omega$
Therefore the circuit is in resonance

$E_{rms}=i_{rms}R=50V$   also power factor=1
av.Power $E_{rms}{i}_{rms}\cos \varphi =250W$