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Q.

For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index (A $\to$ angle of prism)

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a

$μ = 2 \sin (\frac{A}{2})$

b

$μ = c o s (\frac{A}{2})$

c

$μ = 2 c o s (\frac{A}{2})$

d

$μ = \sin (\frac{A}{2})$

answer is B.

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Detailed Solution

$μ = \frac{\sin (\frac{A + d_{m}}{2})}{S i n \frac{A}{2}}$

Here $D_{m} = A$

$\Rightarrow μ = \frac{\sin A}{\sin \frac{A}{2}} = 2 \cos \frac{A}{2}$

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For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index (A → angle of prism)