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Q.

For the Balmer series in the spectrum of H atom, v¯=RH1n121n22 the correct statements among the given are
(l) wavelength increases, the lines in the series converge
(il) The integer n1 is equal to 2
(lll) The lines of longest wavelength corresponds to n2 = 3
(lV) The ionization energy of hydrogen can be calculated from wave number of these lines

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a

(ll), (lll), (IV)

b

(l), (ll), (III)

c

(l), (lll), (IV)

d

(l), (ll), (IV)

answer is B.

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Detailed Solution

 For balmer: n1=2, n2=3,4,5,
v¯=1λ=RH1221n221λlongest =RH122132

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