Q.

For the cell, Hg, Hg2Cl2/ Cl(0.1M) / Cl(0.01M) / Cl2;pt Ecell 0 is 1.10V. Hence, Ecell  is 

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a

1.1591 V

b

–1.1591 V

c

1.0409 V

d

–1.0409 V

answer is A.

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Detailed Solution

Explanation

Stepwise reactions:

2Cl⁻ + 2Hg → Hg₂Cl₂ + 2e⁻ 2e⁻ + Cl₂ → 2Cl⁻

Combined reaction:

2Hg + Cl₂ → Hg₂Cl₂

E° = 1.1 V

Nernst Equation

Ecell = 1.1 - (0.0591 / 2) log([Cl⁻]²cathode / [Cl⁻]anode)

Substituting Values

Ecell = 1.1 - (0.0591 / 2) log((0.01)² / (0.1)²) Ecell = 1.1 - (0.0591 / 2) log(0.01) Ecell = 1.1 - (0.0591 / 2) × (-2) Ecell = 1.1 + 0.0591

Final Answer

Ecell = 1.1591 V

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For the cell, Hg, Hg2Cl2/ Cl− (0.1M) / Cl−(0.01M) / Cl2;pt Ecell 0 is 1.10V. Hence, Ecell  is