For the cell prepared from electrode 
$\mathrm{A}:{\mathrm{Cr}}_2{\mathrm{O}}_7^{2-}{\mathrm{Cr}}^{3+},{\mathrm{E}}_{\text{red }}^{\circ }=+1.33\mathrm{V}$ and electrode
$\mathrm{B}:{\mathrm{Fe}}^{3+}\mid {\mathrm{Fe}}^{2+},{\mathrm{E}}_{\text{red }}^{\circ }=0.77\mathrm{V}$ Which of the following stament is correct? 

The  SRP of B is les than A ,thus electron will flow Fe(B) electrode to Cr(A) electrode.

Fe looses electron so it is negative electrode also Cr will be positve electrode . 

$$\begin{gathered} E_{cell}^o=E_{Cr}^o- E_{Fe}^o \\ = 1.33- 0.77=+0.56V \end{gathered}$$

Hence all statements are correct .