Q.

For the cell reaction:

2Fe(aq)3++2I(aq)-2Fe(aq)2++I2(aq)

Eocell =0.24 V at 298 K. The standard Gibbs energy ΔrG°of the cell reaction is

 [Given that Faraday constant F=96500Cmol-1

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a

-46.32 kJ mol-1

b

46.32 kJ mol-1

c

23.16 kJ mol-1

d

-23.16 kJ mol-1

answer is B.

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Detailed Solution

 The standard Gibbs' energy ΔG°=-nFE°cell   Value of n=2  ΔG°=-2×96500×0.24=-46320 J=-46.32 kJ/mol

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